2w^2/w^2-10w/-12w-28/35

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Solution for 2w^2/w^2-10w/-12w-28/35 equation: 


D( w )

w^2 = 0

w^2 = 0

w^2 = 0

1*w^2 = 0 // : 1

w^2 = 0

w = 0

w in (-oo:0) U (0:+oo)

(2*w^2)/(w^2)-(((10*w)/(-12))*w)-(28/35) = 0

(5/6)*w^2+(2*w^2)/(w^2)-4/5 = 0

5/6*w^2 = -6/5 // : 5/6

w^2 = -36/25

w belongs to the empty set

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